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2x^2-6x+9=7x+7x
We move all terms to the left:
2x^2-6x+9-(7x+7x)=0
We add all the numbers together, and all the variables
2x^2-6x-(+14x)+9=0
We get rid of parentheses
2x^2-6x-14x+9=0
We add all the numbers together, and all the variables
2x^2-20x+9=0
a = 2; b = -20; c = +9;
Δ = b2-4ac
Δ = -202-4·2·9
Δ = 328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{328}=\sqrt{4*82}=\sqrt{4}*\sqrt{82}=2\sqrt{82}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{82}}{2*2}=\frac{20-2\sqrt{82}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{82}}{2*2}=\frac{20+2\sqrt{82}}{4} $
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